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ESX [Decrypted/Asset Escrow Bypassed] Quasar Inventory

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Here's latest version of quasar's inventory for free, fully working and tested, so that you wouldn't have to pay 100 euros for this skidded piece of shit

And don't even tell me lies that this doesn't work, i tested it the fuck out a hundred times, so if you can't install it right, it's not my problem



The virustotal detections are caused by the javascript obfuscation, it's almost impossible to deobfuscate such scale javascript files.
 
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it's not decrypted!! it may work but it's not decrypted!! only ESCROW bypassed!!
 
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it's not decrypted!! it may work but it's not decrypted!! only ESCROW bypassed!!
it is decrypted, but it's decrypted in a very stretched out code, you cannot retrieve the variable names, as in the decryption process whatever decrypter you'd use the local variable names would be lost. If you do want the code to be more readable, you could very easily transform it into a nicer code.
 
it is decrypted, but it's decrypted in a very stretched out code, you cannot retrieve the variable names, as in the decryption process whatever decrypter you'd use the local variable names would be lost. If you do want the code to be more readable, you could very easily transform it into a nicer code.
"you could very easily transform it into a nicer code." this exactly the same answer the guy who created the CPP said... than... you look to the code and suddenly it's not that easy!! I count at least a Thousand variables, all cycles are broken impossible to decrypt. Don't say it's easy when you don't know what you are talking about. The reason there are no real decryption is that it takes a lot of time to develop an accurate decrypter cause all obfuscators use patterns. Anyway I stand my ground...

for i = 48, 57 do L3_1[#L3_1+1] = string.char(i) end for i = 65, 90 do L2_1[#L2_1+1] = string.char(i) end for i = 97, 122 do L2_1[#L2_1+1] = string.char(i) end

This is unusable

Oh and think about this!! Why in hell you would do a For sequence going from 48 to 57...!
And by the way it costs 60€ enough for the lifetime support!
 
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"you could very easily transform it into a nicer code." this exactly the same answer the guy who created the CPP said... than... you look to the code and suddenly it's not that easy!! I count at least a Thousand variables, all cycles are broken impossible to decrypt. Don't say it's easy when you don't know what you are talking about. The reason there are no real decryption is that it takes a lot of time to develop an accurate decrypter cause all obfuscators use patterns. Anyway I stand my ground...

for i = 48, 57 do L3_1[#L3_1+1] = string.char(i) end for i = 65, 90 do L2_1[#L2_1+1] = string.char(i) end for i = 97, 122 do L2_1[#L2_1+1] = string.char(i) end

This is unusable

Oh and think about this!! Why in hell you would do a For sequence going from 48 to 57...!
And by the way it costs 60€ enough for the lifetime support!
lol.
since its obvious that you're just a beginner in lua, the easiest explanation for that code is: these three loops insert characters/numbers by their codes. That is the function string.char, you can find information about this function here: https://www.lua.org/pil/20.html You can also find this code in qb-core and many other scripts, since that's what stackoverflow provided these developers with, in this case i'll drop a qb-core repository link for ya https://github.com/qbcore-framework...8ac5610550c238986a30d1e/shared/main.lua#L6-L8

speaking of everything else you wrote here, 70% is just total nonsense out of not having any knowledge neither in lua or in encrypters/decrypters or obfuscators/deobfuscators. And just so you know, an obfuscator is different from an encrypter, e.g. you cannot decrypt an obfuscated code, or deobfuscate an encrypted code, so please don't mix these two up, you can find more information about it on google.

considering all this bullshit you wrote, there's no reason for me to continue the discussion until you come back with strong knowledge of the lua language, and not the knowledge on searching for answers in stackoverflow.
 
lol.
since its obvious that you're just a beginner in lua, the easiest explanation for that code is: these three loops insert characters/numbers by their codes. That is the function string.char, you can find information about this function here: https://www.lua.org/pil/20.html You can also find this code in qb-core and many other scripts, since that's what stackoverflow provided these developers with, in this case i'll drop a qb-core repository link for ya https://github.com/qbcore-framework...8ac5610550c238986a30d1e/shared/main.lua#L6-L8

speaking of everything else you wrote here, 70% is just total nonsense out of not having any knowledge neither in lua or in encrypters/decrypters or obfuscators/deobfuscators. And just so you know, an obfuscator is different from an encrypter, e.g. you cannot decrypt an obfuscated code, or deobfuscate an encrypted code, so please don't mix these two up, you can find more information about it on google.

considering all this bullshit you wrote, there's no reason for me to continue the discussion until you come back with strong knowledge of the lua language, and not the knowledge on searching for answers in stackoverflow.
I have the original code!!! :D The way you got triggered by this answers the question I was seeking!! Thank you!! by the way... The worst security flaw is the human one, Social Engineering does it's tricks!! Thanks again!
 
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